Binary search isn't just for finding elements in sorted arrays—it's a powerful technique for solving optimization problems where you need to find the "best" partition or cut point in a search space.
The key insight is recognizing when a problem can be transformed into a binary search. This happens when:
For array partition problems, binary search helps you find the optimal way to divide arrays. Instead of checking every possible partition (which would be O(n)), you can eliminate half the search space at each step.
The process follows this pattern:
This approach transforms many O(n) or O(n²) problems into O(log n) solutions. The challenge lies in identifying the right property to search on and designing the evaluation function that can quickly determine which direction to search next.
1def find_partition_point(arr, target_sum):
2 """Find partition point where left sum >= target_sum using binary search"""
3 left, right = 0, len(arr)
4
5 while left < right:
6 mid = (left + right) // 2
7 left_sum = sum(arr[:mid]) # Sum of left partition
8
9 if left_sum >= target_sum:
10 right = mid # Try smaller partition
11 else:
12 left = mid + 1 # Need larger partition
13
14 return left